![sp3d shape sp3d shape](https://lh3.googleusercontent.com/-QysK62b-qZA/YNSkiWTn31I/AAAAAAAAQBE/A6w2mh-nJMgvkknHnqCUsEJgJy5_hVtxwCLcBGAsYHQ/s1600/1624548466903021-0.png)
trigonal bipyramidal is the same, and in this geometry, we can also notice that orbitals of phosphorus i.e. And the shape of PCl₅ will be trigonal bipyramidal, we are helpful for VSEPR theory due to which we can get to know about the molecular shape and its hybridization.Īs we know trigonal bipyramidal is a closed figure so there must be bond angles we can discuss and the amazing fact is that not all the bond angles in PCl₅ hybridization i.e. 5 also represents us about its shape as its shape has five corners and i.e. So we can represent its hybridization as 5 sp3d and the no. And the hybridization of PCl₅ will be sp3d and we will get a set of 5 hybrid orbitals. Q – Explain the hybridization involved in phosphorus pentachloride?Īns: The hybridisation involved in P of PCl₅ is 5 sp³d.Īns: Here we know that outermost electrons or valence electrons are 5 in the case of phosphorus and the orbits are 1s, 3p, and 1d i.e. And in 3rd period elements here in the case of phosphorus there are only 5 valence electrons available. of valence electrons in any elements we can get through its electronic configuration. Because in modern periodic table group numbers represent the valency and no. But it is not possible in group 3 elements. So that PCl6 is not possible as to the formation of PCl6 phosphorus must contain 6 valence electrons then it can form 6 bonds which include coordinate bond or covalent bond. Valency of phosphorus is -3 as it will accept 3 electrons from any other elements to complete its octet and be stable. Some of our important hybridization including s, p, and d orbital are given below:-Īns: PCl6 hybridization will not be possible because of the presence of only 5 valence electrons in case of phosphorus. The molecular geometry of is PCl5 trigonal bipyramid. The energy of 3d ~ energy of 3s ~ energy of 3p as well as e energy of 3d ~ energy of 4s ~ energy of 4p.īecause of the above reason hybridization of 3rd period elements include 3d, 3p, and 3s or 3d, 4s, and 4p ( as the energy of s and p is equivalent to d) and there is also an energy difference between 3p and 4s orbital which led to no hybridization of an element with 3p, 3d and 4s. If we talk for energy then for the 15th group elements like nitrogen, phosphorous (p), arsenic (Ar), antimony (Sb), and bismuth ( Bi) will be in the order:. This hybridization of p in PCl₅ is possible due to the presence of d orbital in phosphorus. So in PCl₅ molecule hybridization of p will be sp3d. In the third period, there are s, p, and s subshells are present. As we know phosphorus belongs to the 3rd period in the modern periodic table. In solid state it will be in charged form. PCl₅ can exist in both solid and gaseous states but is generally found in gaseous states.
![sp3d shape sp3d shape](https://www.zigya.com/application/zrc/images/qvar/CHEN11086611-1.png)
Compound PCl₅ comprises of phosphorus and chlorine in the ratio of P: Cl = 1:5.